3. Mars’ Mean Surface Temperature calculation.
3. Mars’ Mean Surface Temperature calculation. Tmean.mars Surface temp..Tmin..Tmean..Tmax Kelvin...................130.K.....210.K....308.K (1/R²) = (1/1,524²) = 1/2,32 Mars has 2,32 times less solar irradiation intensity than Earth has Mars’ albedo: amars = 0,25 Mars performs 1 rotation every 1,028 day For Mars N = 1 /1,028 = 0,9728 rotations /day (or 0,9728 marsian day /per an earthen day) Mars is a rocky planet, Mars’ surface irradiation accepting factor: Φmars = 0,47 cp.mars = 0,18cal/gr oC, on Mars’ surface is prevalent the iron oxide. β = 150 days*gr*oC/rotation*cal – ( the Rotational Warming Factor constant ). σ = 5,67*10⁻⁸ W/m²K⁴, the Stefan-Boltzmann constant. Mars' Mean Surface Temperature Equation is: Tmean.mars = [ Φ (1-a) So (1/R²) (β*N*cp)¹∕ ⁴ /4σ ]¹∕ ⁴ Tmean.mars = [ 0,47 (1-0,25) 1.361 W/m²*(1/2,32)*(150*0,9728*0,18)¹∕ ⁴ /4*5,67*10⁻⁸ W/m²K⁴ ]¹∕ ⁴ = =( 2.066.635.457,46 )¹∕ ⁴ = 213,21 K Tmean.mars = 213,21 K The calculated Mars’ mean surface temperature Tmean.mars = 213,
30 May 2025