Mercury / Mars satellite measured mean surface temperatures 340 K and 210 K comparison
Mercury / Mars satellite measured mean surface temperatures 340 K and 210 K comparison
These ( Tmean, R, N, and albedo ) planets' parameters are all satellites measured. These planets' parameters are all observations.
Planet….Mercury….Moon….Mars
Tsat.mean.340 K….220 K…210 K
R…......0,387 AU..1 AU..1,525 AU
1/R²…..6.6769….....1….…0,430
N…1 /175,938..1 /29,531..0,9747
a......0,068......0,11......0,250
1-a….0,932……0,89…….0,75
coeff...1,1371.............0,7524
Comparison coefficient calculation
[ (1-a) (1/R²) (N)¹∕ ⁴ ]¹∕ ⁴
Mercury:
Tsat.mean = 340 K
[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =
= [ 0,932*6,6769*(1/175,938)¹∕ ⁴ ] ¹∕ ⁴ = 1,1433
Mars:
Tsat.mean = 210 K
[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =
= [ 0,75*0,430*(0,9747)¹∕ ⁴ ] ¹∕ ⁴ = 0,7524
Let's compare
Mercury coeff. / Mars coeff. =
= 1,1433 /0,7524 = 1,5195
And
Tmean.mercury /Tmean.mars =
= 340 K /210 K = 1,6190
The Mercury's comparison coefficient (1,1433) is calculated for Mercury's Semi-major axis which is 0,387 AU. But half of the time, Mercury comes closer to the sun at its Perihelion of 0,307 AU. The fact Mercury's orbit has high eccentricity e = 0,205 partly explains the difference between the calculated (1,5195) and the measured (1,6190).
Conclusion:
Everything is all right.
It is a demonstration of the Planet Surface Rotational Warming Phenomenon!
And
It is the confirmation that the planet axial spin (rotations per day) "N" should be considered in the (Tmean) planet surface mean temperature equation in the sixteenth root:
Tmean.planet = [ Φ (1-a) So (1/R²) (β*N*cp)¹∕ ⁴ /4σ ]¹∕ ⁴.