The Earth seen from Apollo 17
Europa moon with margins
Earth / Europa (Jupiter's moon) satellite measured mean surface temperatures 288 K and 102 K comparison
It is a demonstration of the Planet Surface Rotational Warming Phenomenon!
All the data below are satellite measurements. All the data below are observations.
Planet….Earth….Europa
Tsat.mean 288 K….102 K
R…...........1 AU…5,2044 AU
1/R²………1…….0,0369
N………....1……1/3,5512 rot./day
a…………..0,306……0,63
(1-a)………0,694……0,37
coeff...0,9127...0,3158
Comparison coefficient calculation
[ (1-a) (1/R²) (N)¹∕ ⁴ ]¹∕ ⁴
Earth:
Tsat.mean = 288 K
[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =
= ( 0,694 * 1 * 1 )¹∕ ⁴ = 0,9127
Europa:
Tsat.mean = 102 K
[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =
= [ 0,37*0,0369*(1/3,5512)¹∕ ⁴ ] ¹∕ ⁴ = 0,3158
Let's compare
Earth coeff. /Europa coeff. =
= 0.9127 /0,3158 = 2,8902
And
Tmean.earth /Tmean.europa =
= 288 K /102 K = 2,8235
Conclusion:
Everything is all right.
It is a demonstration of the Planet Surface Rotational Warming Phenomenon!
Notice:
We could successfully compare Earth /Europa ( 288 K /102 K ) satellite measured mean surface temperatures because both Earth and Europa have two identical major features.
Φearth = 0,47 because Earth has a smooth surface and Φeuropa = 0,47 because Europa also has a smooth surface.
cp.earth = 1 cal/gr*°C, it is because Earth has a vast ocean. Generally speaking almost the whole Earth’s surface is wet. We can call Earth a Planet Ocean.
Europa is an ice-crust planet without atmosphere, Europa’s surface consists of water ice crust, cp.europa = 1cal/gr*°C.
Conclusion:
Everything is all right.
It is a demonstration of the Planet Surface Rotational Warming Phenomenon!
And
It is a confirmation that the planet axial spin (rotations per day) "N" should be considered in the (Tmean) planet mean surface temperature equation in the sixteenth root:
Tmean.planet = [ Φ (1-a) So (1/R²) (β*N*cp)¹∕ ⁴ /4σ ]¹∕ ⁴.