The NEW Planetary Surface Radiative Energy Balance CONCEPT.
The EM energy/ surface matter interaction process - instead of the simplified reflection + heat absorption - the EM energy interaction process leads to a New, a completely different the Planetary Surface Radiative Energy Balance CONCEPT.
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Let's proceed with it systematically. Let's do it scientifically.
Let's begin with the most helpful comparison - Let's begin with Earth's and Moon's average surface temperatures comparison.
Earth's average surface temperature is much higher than Moon's average surface temperature.
Planets and moons are celestial bodies which rotate under the sun. All planets and moons are inevitably subjected to the same Physical Laws.
What we consider happening to the Earth's and to the Moon's temperatures should be necessarily confirmed by the rest planets' and moons' temperatures same behavior.
Earth's average surface temperature is much higher than Moon's average surface temperature.
Why?
What it is the so dramatically different between those two celestial bodies, (Earth and Moon), to have resulted to the so much great average surface temperatures differences?
It was asserted that Earth has an atmosphere, and Moon doesn't have. It was said Earth's atmosphere acts as a blanket, which keeps Earth's surface warm.
What we have discovered, is that the warming-blanket-atmosphere theory is all mistaken. Earth's atmosphere is very thin, and therefore Earth's atmosphere is not capable to warm the surface to any significant extend.
Earth's atmosphere doesn't have any considerable greenhouse warming effect on the surface.
So what else we have?
We have discovered that Earth on average is much warmer than Moon, because Earth rotates very much faster than Moon, and because Earth has a higher the average surface specific heat.
Actually Earth rotates 29,5 times faster than our Moon.
Also Earth's surface is covered with water, and the continents' surface is mostly extremely wet.
On the other hand, Moon's surface is covered with dry lunar regolith.
Actually water has five times (5) higher the specific heat capasity than the dry lunar regolith.
It is 1 cal/gr*oC for water, vs 0,19 cal/gr*oC for dry lunar regolith.
Earth's /Moon's average surface temperatures comparison
The method we use is the "Planets and moons surface temperatures comparison".
We are comparing the various different planets and moons (without-atmosphere, or with a thin atmosphere, Earth included).
Earth and Moon are at the same distance from the sun, and, therefore, Earth and Moon are solar irradiated with the same intensity flux, because at Earth's and Moon's distance from the sun,
the So = 1.361 W/m² (So - it is the Solar constant - the solar flux at the Earth's average distance from the sun 1AU).
We shall first compare the Earth's and Moon's the average surface temperatures
Earth's Tmean = 288K
Earth's "Bond" Albedo a =0,306
Moon's Equator Tmean = 220K (because of the Moon's very slow rotation,
the Equator Tmean ~Tmean =220K)
Moon's "Bond" Albedo a =0,11
Moon - Simple English Wikipedia, the free encyclopedia
In order to compare the Earth's and the Moon's (the satellite measured) average surface temperatures, we shall equalize one of Earth's and Moon's major parameters - we shall equalize their "Bond" Albedo.
Thus we choose to consider having the Moon's "Bond" Albedo changed to Earth's "Bond" Albedo.
By doing so, the Moon's average surface temperature
Tsat.moon =220 K should be changed too.
The simple question begs then:
What should be the Moon's average surface temperature (Tmean), had Moon instead of (a =0,11), the same as Earth's "Bond" Albedo (a =0,306) ?
To do so we shall use the INITIAL PREMISE which says:
For two completely identical planets (or moons), which may differ only in size, their respective average surface temperatures (T1) and (T2) in Kelvin, relate as the fourth root of their respective fluxes (Flux1) and (Flux2) in W/m²:
T1 /T2 = ( Flux1 /Flux2 ) ¹∕ ⁴
Therefore we shall consider two identical Moons, at the same distance from the sun, but having different "Bond" Albedo.
Moon.1 having T1 = 220 K, the a = 0,11
and, minus for Albedo,
Flux1 = (1 - a)So = (1 -0,11)So = 0,89 So (W/m²)
also
Moon.2 having the unknown T2 = (X) K, the a = 0,306
and, minus for Albedo,
Flux2 = (1 - a)So = (1 - 0,306)So = 0,694 So (W/m²)
When substituting in the INITIAL PREMISE equation we shall have:
220 K /(X) K = [ (0,89 So) /(0,694 So) ] ¹∕ ⁴
For Albedo equal to Earth's a =0,306 the Moon's Tmean would be:
(X) K = 220 K /[ (0,89 So) /(0,694 So) ] ¹∕ ⁴ =
= 220 K /(1,2824) ¹∕ ⁴ = 220 K /1,0642 =
= 206,7 K
(X) K = 206,7 K
Consequently, for equal average Albedo a=0,306
the mean surface temperatures
Tmean.earth = 288K
vs Tmean.moon = 206,7K
because Earth and Moon share the same intensity solar flux So = 1.361 W/m² , and therefore it makes the comparison most simple.
Because there is only one major parameter between Earth and Moon to compare has left -
the comparison for Earth and Moon,
their (N*cp) products' sixteenth root:
( N*cp )^1/16
So we shall have:
Tmean.earth /Tmean.moon =
= 288K /206.7K = 1.3933
and the comparison for Earth and Moon,
their (N*cp) products' sixteenth root:
[ Earth(N*cp) /Moon(N*cp) ]^1/16 =
= [ (1*1) /(0,0339*0,19)] ^1/16 =
= (155,42)^1/16= 1,3709
where
N.earth = 1 rot/day
N.moon = 0,0339 rot/day
Earth’s cp = 1 cal/gr*oC (oceanic waters, and land mostly wet)
Moon's cp = 0,19 cal/gr*oC (dry lunar regolith)
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When we look at the results of the two comparisons, (1,3933) and (1,3709), we recognize that they are almost identical.
They differ only by 1,63 %.
It is a demonstration of the Planet Surface Rotational Warming Phenomenon:
Planets' and moons' mean surface temperatures relate (everything else equals) as their (N*cp) products' sixteenth root.
(Tmean.planet.1) /(Tmean.planet.2) =
= [ (N1*cp1) /(N2*cp2) ] ^ 1/16
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For equal Albedo, Earth's and Moon's (the satellite measured) average surface temperatures,
Tsat.earth
and Tsat.moon,
relate as their (N*cp) products' sixteenth root.
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