Earth / Mars satellite measured mean surface temperatures 288 K and 210 K comparison
It is a demonstration of the Planet Surface Rotational Warming Phenomenon!
These ( Tmean, R, N, cp and albedo ) planets' parameters are all satellites measured.
These planets' parameters are all observations.
Planet…....Earth.….Moon….Mars
Tsat.mean.288 K….220 K…210 K
R…...............1... AU..1 AU..1,525 AU
1/R²…..........1…........1….…0,430
N…..............1....1 /29,531..0,9747
cp................1.........0,19.......0,18
a..............0,306......0,11......0,250
1-a…........0,694……0,89…….0,75
(1-a)¹∕ ⁴…0,9127....0,9713…0,9306
coeff...........1...................0,72748
As we can see Earth and Mars have very close values for (1-a)¹∕ ⁴ term;
For Earth (1-a)¹∕ ⁴ = 0,9127 and for Mars (1-a)¹∕ ⁴ = 0,9306.
Also Earth and Mars have very close N; for Earth N = 1 rotation /day, and for Mars N = 0,9747 rotation /day.
Earth and Mars both have the same Φ = 0,47 solar irradiation accepting factor.
Thus the comparison coefficient can be limited as follows:
Comparison coefficient calculation
[ (1/R²) (cp)¹∕ ⁴ ]¹∕ ⁴
Earth:
Tsat.mean = 288 K
[ (1/R²)*(cp)¹∕ ⁴ ]¹∕ ⁴ =
= [ 1*(1)¹∕ ⁴ ] ¹∕ ⁴ = 1
Mars:
Tsat.mean = 210 K
[ (1/R²)*(cp)¹∕ ⁴ ]¹∕ ⁴ =
= [ 0,430*(0,18)¹∕ ⁴ ] ¹∕ ⁴ = ( 0,430*0,65136 )¹∕ ⁴ =
= ( 0,2801 )¹∕ ⁴ = 0,72748
Let's compare
Earth coeff. / Mars coeff. =
= 1 /0,72748 = 1,3746
And
Tmean.earth /Tmean.mars =
= 288 K /210 K = 1,3714
Conclusion:
Everything is all right.
It is a demonstration of the Planet Surface Rotational Warming Phenomenon!
And
It is the confirmation that the planet surface specific heat "cp" should be considered in the (Tmean) planet mean surface temperature equation in the sixteenth root:
Tmean.planet = [ Φ (1-a) So (1/R²) (β*N*cp)¹∕ ⁴ /4σ ]¹∕ ⁴.